Определение величины полуосей по двум точкам |
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676a^2+289b^2=1 |
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ε=c/a |
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Точки
эллипса: |
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625a^2+324b^2=1 |
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ε= |
0.560112034 |
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M |
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26 |
17 |
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a^2=676/(1-289/b^2)=625/(1-324/b^2) |
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c=(a^2-b^2)^0,5 |
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N |
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25 |
18 |
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b^2=289/(1-676/a^2)=324/(1-625/a^2) |
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c= |
18.55243157 |
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676-676*324/b^2=625-625*289/b^2 |
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d=a/ε |
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289-289*625/a^2=324-324*676/a^2 |
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d= |
±59,1358756231299 |
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(676*324-625*289)/b^2=676-625 |
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R1=b^2/a |
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(289*625-324*676)/a^2=289-324 |
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R2=a^2/b |
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38399/b^2=51 |
r1=|F1A|=((x+c)^2+y^2)^0,5=a+x*ε |
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-38399/a^2=-35 |
r2=|F2A|=((x-c)^2+y^2)^0,5=a-x*ε |
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b= |
27.43941633 |
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a= |
33.12271555 |
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